fixed issue 1839: catch exception if source code cannot be opened in the debugger
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@@ -54,9 +54,13 @@ def interact():
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filename = web_debugger.filename
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lineno = web_debugger.lineno
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if filename:
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# prevent IOError 2 on some circuntances (EAFP instead of os.access)
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try:
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lines = open(filename).readlines()
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except:
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lines = ""
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lines = dict([(i + 1, l) for (i, l) in enumerate(
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[l.strip("\n").strip("\r") for l
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in open(filename).readlines()])])
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[l.strip("\n").strip("\r") for l in lines])])
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filename = os.path.basename(filename)
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else:
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lines = {}
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