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populate list without duplicates, thanks simonm3

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This commit is contained in:
mdipierro
2012-07-11 18:21:41 -05:00
parent 15944354cc
commit 0032154bd9
2 changed files with 5 additions and 14 deletions
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VERSION
+1 -1
View File
@@ -1 +1 @@
Version 2.00.0 (2012-07-11 18:16:55) dev
Version 2.00.0 (2012-07-11 18:21:38) dev
gluon/contrib/populate.py
+4 -13
View File
@@ -103,11 +103,8 @@ def populate(table, n, default=True, compute=False):
elif field.type=='list:integer' and hasattr(field.requires,'options'):
options=field.requires.options(zero=False)
if len(options) > 0:
vals = []
for i in range(0, random.randint(0,len(options)-1)/2):
vals.append(options[random.randint(0,len(options)-1)][0])
record[fieldname] = vals
elif field.type =='integer':
record[fieldname] = [item[0] for item in random.sample(options, random.randint(0,len(options)-1)/2)]
elif field.type == 'integer':
try:
record[fieldname] = random.randint(field.requires.minimum,field.requires.maximum-1)
except:
@@ -143,19 +140,13 @@ def populate(table, n, default=True, compute=False):
ids[tablename] = [x.id for x in table._db(table._db[field.type[15:]].id>0).select()]
n = len(ids[tablename])
if n:
vals = []
for i in range(0, random.randint(0,n-1)/2):
vals.append(ids[tablename][random.randint(0,n-1)])
record[fieldname] = vals
record[fieldname] = [item[0] for item in random.sample(ids[tablename], random.randint(0,n-1)/2)]
else:
record[fieldname] = 0
elif field.type=='list:string' and hasattr(field.requires,'options'):
options=field.requires.options(zero=False)
if len(options) > 0:
vals = []
for i in range(0, random.randint(0,len(options)-1)/2):
vals.append(options[random.randint(0,len(options)-1)][0])
record[fieldname] = vals
record[fieldname] = [item[0] for item in random.sample(options, random.randint(0,len(options)-1)/2)]
elif field.type=='string' and hasattr(field.requires,'options'):
options=field.requires.options(zero=False)
record[fieldname] = options[random.randint(0,len(options)-1)][0]